- Thread starter
- #1

- Thread starter Cbarker1
- Start date

- Thread starter
- #1

- Admin
- #2

- Feb 14, 2012

- 3,894

In our case ($\cos3x+4h \cos x$), we need to express $\cos 3x$ in terms of $\cos x$ since the second term has a $\cos x$ in it.

By using the triple-angle formula for $ \cos 3x$, where $ \cos 3x=4\cos^3x-3 \cos x$, we can simplify the original expression as follows:

$\displaystyle \cos3x+4h \cos x =(4\cos^3x-3 \cos x)+4h \cos x=\cos x(4\cos^2x-3+4h)$

- Thread starter
- #3

- Admin
- #4