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$$

\int_{\gamma}ze^{z^2}dz

$$

$\gamma(t) = 2t + i -2ti$, for $0\leq t\leq 1$.

$

\int_{\gamma} f(\gamma(t))\gamma'(t)dt

$

But

$

\int_{\gamma}ze^{z^2}dz \Rightarrow \frac{1}{2}\int e^wdw

$

So then I would be solving

$$

\frac{1}{2}\int\exp(4t-1+4ti-8t^2i)(4+4i-16ti)dw

$$

Correct? And how would I find the appropriate bounds for this integral or would it still be 0 and 1?

\int_{\gamma}ze^{z^2}dz

$$

$\gamma(t) = 2t + i -2ti$, for $0\leq t\leq 1$.

$

\int_{\gamma} f(\gamma(t))\gamma'(t)dt

$

But

$

\int_{\gamma}ze^{z^2}dz \Rightarrow \frac{1}{2}\int e^wdw

$

So then I would be solving

$$

\frac{1}{2}\int\exp(4t-1+4ti-8t^2i)(4+4i-16ti)dw

$$

Correct? And how would I find the appropriate bounds for this integral or would it still be 0 and 1?

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