- #1
Leo Liu
- 353
- 156
- Homework Statement
- This is a conceptual question.
- Relevant Equations
- $$ \vec{\tau}=I \vec{A} \times \vec{B} $$
Can anyone please tell me why the torque on a circular current loop can be calculated by the equation below? In other words, what is the intuition for the formula? Thank you. (I modified my question to a particular case)
$$ \vec{\tau} = I \vec{A} \times \vec{B} $$
$$ \vec{\tau} = I \vec{A} \times \vec{B} $$
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