Tides and centrifugal force help

In summary, the conversation discusses the phenomenon of tides and the factors that contribute to them. The main causes identified are the gravitational pull of the moon and the Earth, as well as the centrifugal force. There is also a mention of a potential explanation involving the rotation of the Earth and the moon. The conversation ends with a request for assistance in solving equations related to tidal prediction.
  • #1
ponjavic
225
0
Ok so I'm reading up on some physical (no that's probably not the right word, enlighten me!) phenomenas in this case the tides.

So as far as I've understood the water on the surface towards the moon is affected both by Earth's gravity (which is bigger) and the moon's, and therefore positions itself in between them (a bit above Earth's surface).

What I don't understand is the similar occurance at the surface away from the moon where a similar high tide is caused. From the explanation I could get of the web I got that there is a centrifugal force acting outwards from the Earth's center which is bigger than the moon's gravity and therefore there is a net force acting out from Earth's center gathering the water.

I can't grasp how the tides are supposed to be similar (which the article states, they are equal) since the centrifugal force should be added to the moon's gravity on one side and subtracted on the other.
Next, what is a centrifugal force, we recently spent 2 lessons discarding our believes that a person in a loop (rollercoaster) is effected by an outward force. Now I am being told that the Earth is experiencing an outward force?

The article's explanation was. If you look at it in a frame of reference where the Earth moves naturally around the moon without an inward net force (uuhh what?) a net force would be outwards coming from the counterforce on the centripetal force, Newton's third law. (This probably doesn't make any sense but you might understand what I'm trying to say). Either way I don't get it, could someone explain?
 
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  • #2
What you are saying makes some sense but it is not the cause of the tides. consider this crude drawing
M WEW
this is the moon on the left the Earth on the right and water surrounding it.

now cosider the magnitude of the gravitation force of the moon on all three of these things i.e. the Earth and two waters.

<<<W <<E <W

the water on the moon side get the strongest pull towards the moon. then the Earth as a whole get a less strong pull and then the water on the far side of the Earth get the least pull because it is farther away from the moon.
So let's just say for simplicity that the pull of the moon pulls the close water 3 meters towards it, it pulls the Earth 2 meters towards it and it pulls the far water 1 meter towards it.
again if we refer to the diagram, compared to the Earth the water close to the moon is getting pulled 1 meter towards the moon, compared to the earth, and the water on the far side is getting pushed away from the Earth because the moon is pulling the Earth more than the far side water.
<W E W>

I tried to make it as clear a possible. hopefully you understand
 
  • #3
Ok it sounds quite resonable but for what reason would other explanations I've seen include centrifugal forces?

One more thing, In the WE situation the Earth's gravitation is counteracting the moons gravitation while in the other it's adding to the moon's pull, how can the tides be equal?
 
  • #4
the Earth's gravitation would not affect the tides because the Earth pull evenly on water on both sides cancelling it out. you can't include the Earth's pull because it doesn't actually cause the water to move. I see what you mean that the Earth's & moon's pulls should be more but I don't believe that is the case. Sorry, but I am having a hard time putting this into words.

would you have a link to these sources that involve centripedal (see as centrifugal is only a ficticious force) force?
 
  • #5
http://en.wikipedia.org/wiki/Tide
this wasn't as in depth as another one I found about the frame of reference but it should be enough, I'll try to find the other one too
 
  • #6
May I point out this from your webpage. I would be highly skeptical considering the source. here is where I learned of the reason for tides. It was written by a Phd astronomer who has written many several papers and also a book.
 
  • #7
http://www.coastalresearch.nl/tides.htm

The interesting thing with this article is that herer the cause of the second tide away from the moon is caused by the rotation of the moon/earth as opposed to your theory (which I have also seen in other articles) it is caused simply by gravity...
Elaborate :P
 
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  • #8


I have a problem in solving the shallow water equations using the differences identified in Matlab for the purpose of the work of a predictive model and tidal in the Arabian Gulf Is there anyone who can help me please help and guide everyone who has information
 

Related to Tides and centrifugal force help

1. What is the relationship between tides and centrifugal force?

The gravitational pull of the moon and sun causes the Earth's oceans to bulge, creating tides. However, the Earth's rotation also creates centrifugal force which counteracts the pull of gravity, resulting in a slight decrease in the strength of tides.

2. How does centrifugal force affect tides?

Centrifugal force creates a slight decrease in the strength of tides by counteracting the pull of gravity. This is due to the Earth's rotation creating a slight outward force, causing the water to spread out and decrease the overall height of tides.

3. What role does the moon play in tides?

The moon plays a significant role in creating tides due to its gravitational pull on the Earth's oceans. The moon's position and phase can also affect the strength and height of tides, with the strongest tides occurring during a full or new moon.

4. Are tides affected by the sun as well?

Yes, the sun also plays a role in creating tides. While the moon's gravitational pull is stronger, the sun's pull is still significant and can amplify or diminish the effects of tides depending on its position and phase.

5. How does the Earth's rotation impact tides?

The Earth's rotation creates centrifugal force which counteracts the gravitational pull of the moon and sun, resulting in a slight decrease in the strength of tides. Additionally, the rotation of the Earth also causes the tides to shift and change over time, known as the tidal cycle.

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