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Billyboy777
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Hi all, I've been trying to find an answer to this question for a while, (bear with me physics is not a strong point). I would like to know how one would go about calculating how fast you have to throw a ball out of a train to negate its forward momentum. My understanding is that if you throw the ball straight out of the back you just need to match the trains speed, but what happens if you throw the ball at a diagonal? If i considered straight out of the side of the train to be 90degrees and out the back to be zero degrees, does the ball need to be thrown harder to compensate for the shallower angle and if so by how much?