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- Homework Statement
- We try with a thin convergent lens, by moving it on its optical axis, to project on a fixed screen the image of a small object located in the optical axis. This is only possible with two position of the lens ##I_1=20cm## and ##I_2=80cm##. Determine the ##d## distance from the object to the screen and focal length ##f## of the lens.
- Relevant Equations
- ##\frac{1}{p}+\frac{1}{q}=\frac{1}{f}##
##d=q+p##
Where ##p## is the distance of the object from the lens and ##q## is the distance between the image and the lens.
Since ##d=q+p \implies q=d-p##
\begin{cases}
\frac{1}{I_1}+\frac{1}{d-I_1}=\frac{1}{f}\\
\frac{1}{I_2}+\frac{1}{d-I_2}=\frac{1}{f}
\end{cases}
Is this correct?
\begin{cases}
\frac{1}{I_1}+\frac{1}{d-I_1}=\frac{1}{f}\\
\frac{1}{I_2}+\frac{1}{d-I_2}=\frac{1}{f}
\end{cases}
Is this correct?