Thevenin's equivalent circuit problem

In summary, the conversation discusses using Thevenin's theorem to find the current in a 3 ohm parallel branch resistor. The attempt at a solution raises the question of whether it is possible to use Thevenin's theorem in this circuit and suggests using Norton's equivalent circuit instead. The conversation also includes a link to a website for further study and ends with a thank you.
  • #1
backstance
14
0

Homework Statement


use thevenin's theorem to find the current in the 3 ohm, parallel branch, resistor

http://img217.imageshack.us/img217/909/img0267cc7.jpg

Homework Equations


Thevenin equivalent circuit, voltage divider rule

The Attempt at a Solution



I don't think its possible, since thevenin's theorem ends up with a voltage source and a resistor in series, you can only find currents and voltages in components that are in series. In this circuit there is nowhere to make the cut and split the circuit across terminals A and B. Normally you'd need Norton's equivalent circuit to find the current in the 3ohm resistor. Am I right, or is there actually a solution using thevenin's?
 
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  • #2
backstance said:

Homework Statement


use thevenin's theorem to find the current in the 3 ohm, parallel branch, resistor

http://img217.imageshack.us/img217/909/img0267cc7.jpg


Homework Equations


Thevenin equivalent circuit, voltage divider rule


The Attempt at a Solution



I don't think its possible, since thevenin's theorem ends up with a voltage source and a resistor in series, you can only find currents and voltages in components that are in series. In this circuit there is nowhere to make the cut and split the circuit across terminals A and B. Normally you'd need Norton's equivalent circuit to find the current in the 3ohm resistor. Am I right, or is there actually a solution using thevenin's?

Could anyone solve this problem?
 

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  • #3
any ideas? any help would be appreciated, thanks!
 
  • #4
http://www.allaboutcircuits.com/vol_1/chpt_10/8.html
try and study it from the url. The circuit is quite the same as yours.
 
  • #5
thanks for that, useful!
 
  • #6
ur most welcome! :D
 

Related to Thevenin's equivalent circuit problem

What is Thevenin's equivalent circuit problem?

Thevenin's equivalent circuit problem is a method used to simplify a complex electrical circuit into a single equivalent circuit. This equivalent circuit contains a voltage source, a resistor, and an internal resistance. It allows for easier analysis and understanding of the overall behavior of the circuit.

When is Thevenin's equivalent circuit problem used?

Thevenin's equivalent circuit problem is used when analyzing circuits with multiple resistors and voltage sources. It is often used in electrical engineering and circuit design to simplify complex circuits into a single equivalent circuit for easier analysis.

How is Thevenin's equivalent circuit calculated?

Thevenin's equivalent circuit is calculated by replacing the complex circuit with an equivalent voltage source, resistor, and internal resistance. The voltage source is equal to the open-circuit voltage of the original circuit, and the resistor is equal to the total resistance of the original circuit when all voltage sources are turned off. The internal resistance is the equivalent resistance between the two terminals of the original circuit.

What are the advantages of using Thevenin's equivalent circuit?

Thevenin's equivalent circuit allows for easier analysis and understanding of complex circuits. It also simplifies the process of finding the maximum power transfer and the effect of load variations on the circuit. Additionally, it can be used to determine the behavior of a circuit without needing to know all of the details of its internal components.

Are there any limitations to Thevenin's equivalent circuit?

There are some limitations to Thevenin's equivalent circuit. It can only be used for linear circuits, meaning that the voltage and current relationship must follow Ohm's law. It also assumes that the circuit is in a steady state and does not take into account any transient effects. In some cases, the equivalent circuit may not accurately represent the behavior of the original circuit.

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