No, your equation looks okay now. I was worried about the sign of the term for for the 100 Ω resistor. Keep going :)bnosam said:I'm solving for voltage at this point so I can find the thevenin voltage.
For the second equation would it be:
1310 IB + 100(IB - IA) = -4*10-5 V2
Or did you mean I have the sign for V2 wrong
You seem to have lost an order of magnitude in the second term: 100 x 500 x 10-6 = 5 x 10-2 = 1/20 . You also dropped the v2 on the right hand side.bnosam said:1410 IB - 5000*10-6 = -4*10-5
Okay. Fix your second term above and re-solve.So now I need an equation for V2:
(-80IB )*(50000)
= -4 000 000 IB
Looks good. So What's v2?bnosam said:1410 IB - 50000*10-6 = -4*10-5 V2
V2 = (-80IB)(50000 Ω)
so IB = 4 * 10-5
Also looks good.bnosam said:V2 = - 160V
Hook up a test charge on the outside of the circuit to find that out?gneill said:Also looks good.
Now, how are you going to approach the Thevenin resistance?
You mean a voltage source? Yes, I suppose that would work.bnosam said:Hook up a test charge on the outside of the circuit to find that out?
Before dependent sources, the only way I've been shown how to do it was just by combining resistors. Then I was shown this whole Etest/Itest method and I have no idea how to grasp it really. I've had one example of it.gneill said:You mean a voltage source? Yes, I suppose that would work.
I have another suggestion though. Do you know the way Thevenin and Norton models are related? If you could determine the short circuit current (at the output) fairly easily, would that help?
A Thevenin equivalent circuit with a dependent source is a simplified representation of a complex circuit that contains a dependent source (such as a voltage-controlled voltage source or current-controlled current source). It is used to model the behavior of the original circuit and is often used in circuit analysis and design.
The Thevenin equivalent circuit with a dependent source is calculated by first finding the open-circuit voltage (VOC) and the short-circuit current (ISC) of the original circuit. Then, the equivalent voltage source (VTH) is equal to VOC and the equivalent resistance (RTH) is equal to VOC/ISC. The dependent source is then incorporated into the equivalent circuit using its controlling variable (such as a voltage or current).
Using a Thevenin equivalent circuit with a dependent source can simplify complex circuits and make them easier to analyze and design. It also allows for the use of standard circuit analysis techniques, such as Ohm's law and Kirchhoff's laws. Additionally, it can provide insight into the behavior of the original circuit and help identify potential issues or improvements.
Yes, a Thevenin equivalent circuit with a dependent source can be used for any type of circuit, as long as it contains a dependent source. This includes circuits with resistors, capacitors, inductors, and other components. However, the resulting equivalent circuit may not always accurately model the behavior of the original circuit, so it is important to carefully consider the assumptions and limitations of the Thevenin equivalent circuit.
The validity of a Thevenin equivalent circuit with a dependent source can be verified by comparing its predictions to the behavior of the original circuit. This can be done by simulating the circuits using software or by performing experiments on physical circuits. If the results match closely, then the equivalent circuit can be considered valid for the given range of values of the dependent source's controlling variable.