- #1
wubie
Hello,
It has been over a year since I last did calculus. And I am having trouble with my current calculus course. First here is the question:
Solve the given first-order linear equation and verify that your solution indeed satisfies the equation.
y' - 2xy = 2xe^x^2
Now I THINK I have the answer:
y = e^x^2 ( x^2 + c)
But how do I verify? I would think I simply would take the above equation and it's derivative and sub. into the equation
y' - 2xy = 2xe^x^2
If that is the case, my problem is this: When I take the derivative of
y = e^x^2 ( x^2 + c)
I have
y' = 2x * e^x^2 + 2x^3 * e^x^2 + 2x * C * e^x^2
How can I verify my answer when there is an unknown constant in my derivative? What am I missing?
Any help is appreciated - detailed if possible. Thankyou.
It has been over a year since I last did calculus. And I am having trouble with my current calculus course. First here is the question:
Solve the given first-order linear equation and verify that your solution indeed satisfies the equation.
y' - 2xy = 2xe^x^2
Now I THINK I have the answer:
y = e^x^2 ( x^2 + c)
But how do I verify? I would think I simply would take the above equation and it's derivative and sub. into the equation
y' - 2xy = 2xe^x^2
If that is the case, my problem is this: When I take the derivative of
y = e^x^2 ( x^2 + c)
I have
y' = 2x * e^x^2 + 2x^3 * e^x^2 + 2x * C * e^x^2
How can I verify my answer when there is an unknown constant in my derivative? What am I missing?
Any help is appreciated - detailed if possible. Thankyou.