mrausum said:so how do i do the question?
mrausum said:well it hasn't given the mass. But are you saying work out v from E=1/2mv^2, then f from E/h. Then wavelength from lamda=v/f?
HjGanap said:how do you get lambda = h/mv
i know E = hc/lambda = h/mv
so, if i combine both equations, shouldn't i suppose to get lambda = cmv ?
did i miss something or what.
The Brogile wavelength of an Alpha particle refers to the wavelength of the particle when it is in motion. It is determined by dividing the Planck's constant by the momentum of the particle.
The Brogile wavelength of an Alpha particle can be calculated using the equation λ = h/mv, where λ is the wavelength, h is Planck's constant, m is the mass of the particle, and v is its velocity.
The Brogile wavelength of an Alpha particle is significant because it shows the wave-like behavior of particles at the atomic level. It also helps in understanding the behavior and properties of particles at the quantum level.
The Brogile wavelength and energy of an Alpha particle are inversely proportional. This means that as the wavelength decreases, the energy of the particle increases and vice versa.
No, the Brogile wavelength of an Alpha particle cannot be observed directly as it is too small to be detected by any instrument. However, its effects can be observed through various experiments and calculations.