- Thread starter
- Moderator
- #1

\[\int_0^{\infty}e^{-x^2}\,dx=\frac{\sqrt{\pi}}{2}\]

This is inline: \(\frac{\sqrt{b^2-4ac}}{2a}\)

Other centered equation

$$\Gamma(x)=\int_0^{\infty}e^{-t}t^{x-1}\,dt $$

This is inline: \(\frac{\sqrt{b^2-4ac}}{2a}\)

Other centered equation

$$\Gamma(x)=\int_0^{\infty}e^{-t}t^{x-1}\,dt $$

Last edited: