- #1
ombudsmansect
- 29
- 0
Hey guys was wondering if anyone knew what the go is with linearly dependent solutions to test for exactness, by that I mean
I have the differential equation (2x + y^2)dx + 4xydy = 0 (M,N)
So i test for exactness and
[tex]\partial[/tex]M/[tex]\partial[/tex]y = 2y [tex]\partial[/tex]N/[tex]\partial[/tex]x = 4y
So I wanted to ask if this does prove exactness, given that they are linearly dependent I cannot find an integrating factor, but I am not sure if I can just proceed to solve anyway
I have the differential equation (2x + y^2)dx + 4xydy = 0 (M,N)
So i test for exactness and
[tex]\partial[/tex]M/[tex]\partial[/tex]y = 2y [tex]\partial[/tex]N/[tex]\partial[/tex]x = 4y
So I wanted to ask if this does prove exactness, given that they are linearly dependent I cannot find an integrating factor, but I am not sure if I can just proceed to solve anyway