Tension in the string holding a falling chain

In summary: The speed of the bottommost tip of the right string is ##2\sqrt{2g(\frac{y}{2})}## .In summary, the Homework Equations state that the tension in the suspending chain is equal to the weight of the chain plus the change in momentum per time of the chain. The Attempt at a Solution calculates the tension to be equal to the weight of the chain plus the change in momentum per time of the chain plus the speed of the bottommost tip of the right string.
  • #36
TSny said:
I'm afraid I don't follow your argument.

Now ,even I don't follow my argument ?:)

The remarkable thing is that ,despite getting the dynamics of the problem wrong in every step ,I got the correct answer in first try o_O .
 
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  • #37
Vibhor said:
The remarkable thing is that ,despite getting the dynamics of the problem wrong in every step ,I got the correct answer in first try o_O .
That's happened to me before, too.
 
  • #38
TSny said:
That's happened to me before, too.

:smile:

Thanks a lot Sir .

Thank you very much @haruspex .
 

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