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Taylor series

Petrus

Well-known member
Feb 21, 2013
739
Hello MHB,
I understand taylor series proof with one variable but how does it work with Two variabels? is it pretty much the same? The one I understand is

Taylor's theorem - Wikipedia, the free encyclopedia
Go to proofs Then it's the one under "Derivation for the integral form of the remainder"

Regards,
\(\displaystyle |\pi\rangle\)
 

Klaas van Aarsen

MHB Seeker
Staff member
Mar 5, 2012
8,854
Hello MHB,
I understand taylor series proof with one variable but how does it work with Two variabels? is it pretty much the same? The one I understand is

Taylor's theorem - Wikipedia, the free encyclopedia
Go to proofs Then it's the one under "Derivation for the integral form of the remainder"

Regards,
\(\displaystyle |\pi\rangle\)
Yep. It's pretty much the same.
Note that the symbol $D^\alpha f(\mathbb a)$ is a vector for $\alpha = 1$, a matrix for $\alpha = 2$, a 3-dimensional matrix for $\alpha = 3$, and so on.