Tank outlet velocity exit pipe cross-section area dependence

In summary: However, this basic principle of flow rate in relation to output section area can be used to calculate the velocity at any point along the pipe.In summary, the velocity at the outlet of the pipe is higher in case 2 than in case 1.
  • #1
Dileep Ramisetty
3
0
tank.png

Sir, actually in a tank by the toricelli's law and also from bernoulli equation, we have outlet velocity as V= (2*g*H)^(1/2). In the case 2, I have closed the pipe exit partially with hand and observed a higher velocity than case 1, in practical. but when I applied the bernoulli equation at the surface of tank and pipe's outlet in the both cases, I am getting velocity V=(2*g*H)^(1/2) by energy conservation. But in practical the velocity is high in case 2.
so, someone please solve me this, by considering the bernoulli energy equation at 1.the surface of tank and 2.at pipe exit
Thank you
 
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  • #2
The mean depth at the outlet is greater in case 2 than in case 1 .

This should only make a noticeable difference though if the nominal mean depth is only equal to a small number of outlet pipe diameters .

You don't say how you measured the velocity . Simple visual estimates of flow velocity can be very inaccurate and you may have just overestimated the difference in flow velocity for the two cases .
 
Last edited:
  • #3
Lets check both figures and let's forget for a while the pipes at the bottom of the tanks:

Neglecting everything about fluid dynamics, and centering only on basic physics ...

The fluid inside the tank will flow down at a speed of:

V= sqrt(dens g h). If the surface area of the free surface is "S", the flowrate will be: Q= S x VLets now have a look to the output pipe at the bottom, and let's assume, the height of the exit, in both cases to be the same.

If the pipe section area is given by "A" and the output speed by "Ve", the output flowrate will be: Qo= Ve x AContinuity equation (and common sence) says that in "ideal" conditions, Flowrate at which the tank level goes down, must be equal to the output flowrate, hence ...

Q= Qo
S x V= Ve x A

Ve= V x S/A


Meaning that ... The less output section area "A", the higher output speed "Ve".The real world is not so "perfect". Fluids do not tend to behave so simply and many variables have to be taken into account.
 

Related to Tank outlet velocity exit pipe cross-section area dependence

1. What is tank outlet velocity exit pipe cross-section area dependence?

Tank outlet velocity exit pipe cross-section area dependence refers to the relationship between the size of the outlet pipe and the velocity of the liquid flow from a tank. As the cross-section area of the pipe decreases, the velocity of the liquid exiting the tank increases.

2. How does the cross-section area of the outlet pipe affect the flow rate from the tank?

The cross-section area of the outlet pipe directly affects the flow rate from the tank. A smaller pipe area will result in a higher velocity and therefore a higher flow rate, while a larger pipe area will result in a lower velocity and flow rate.

3. Is there an ideal cross-section area for the outlet pipe?

The ideal cross-section area for the outlet pipe depends on the specific tank and its intended use. Factors such as the desired flow rate, pressure, and viscosity of the liquid should be taken into consideration when determining the optimal pipe size.

4. How does the density of the liquid affect the tank outlet velocity?

The density of the liquid does not have a direct effect on the tank outlet velocity. However, it can affect the overall flow rate as it can impact the pressure and viscosity of the liquid, which in turn can impact the velocity through the outlet pipe.

5. Can I change the tank outlet velocity by adjusting the cross-section area of the outlet pipe?

Yes, the tank outlet velocity can be changed by adjusting the cross-section area of the outlet pipe. A larger area will result in a lower velocity and a smaller area will result in a higher velocity. This is known as the continuity equation in fluid mechanics.

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