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Tangents and distance formula

Niall

New member
Apr 24, 2013
1
The tangent P(3,9) on the curve y = x^2, cuts the x-axis at T and PN is perpendicular to the x-axis. Find the length of TN.

So far I have:

dy/dx = 2x
dy/dx = 6

y - 9 = 6(x - 3)
y = 6x - 9

Making point T (3/2, 0), but how do you find point N?

Thank you.
 

ZaidAlyafey

Well-known member
MHB Math Helper
Jan 17, 2013
1,667
We have got that PN is perpendicular to the x-axis what do we conclude ?