- #1
archaic
- 688
- 214
- Homework Statement
- Given ##x=t^2-6## and ##y=t^3+3t##, what is the equation of the tangent to the curve when ##t=3##.
- Relevant Equations
- ##m=y'(t)/x'(t)##
##x(3)=9-6=3##, ##y(3)=27+9=36##.
##\frac{y'(3)}{x'(3)}=\frac{3\times9+3}{2\times3}=\frac{30}{6}=5##.
##y=5(x-3)+36=5x+21##.
##\frac{y'(3)}{x'(3)}=\frac{3\times9+3}{2\times3}=\frac{30}{6}=5##.
##y=5(x-3)+36=5x+21##.