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#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

I am doing some old exam and got less knowledge for this problem.

consider the graph of the function

\(\displaystyle g(x)=\frac{1}{x}, \ x\neq 0\)

the point \(\displaystyle \left(3,-1 \right)\) lies on two tangents to the graph. Decide tangents equation.

My progress

well I derivate and find the slope

\(\displaystyle g'(x)=\ln(x)\) so the slope is \(\displaystyle m=\ln(3)\)

so the tangents equation is \(\displaystyle y=\ln(3)(x-3)-1\) is this correct? I am supposed to get two tangent equation

Regards,

\(\displaystyle |\pi\rangle\)