Taking the time derivative of a curl

In summary, the time derivative of a curl is commutative only for the partial time derivative in cartesian coordinates. However, in spherical and cylindrical coordinates, the total time derivative and the partial derivative in curvilinear coordinates are not commutative due to the dependence of unit vectors on time. Additionally, it is important to distinguish between coordinate variables and position variables, as the time derivative and curl are operations on a field, not an object's position.
  • #1
nabeel17
57
1
Is the time derivative of a curl commutative? I think I may have answered this question... Only the partial time derivative of a curl is commutative? The total time derivative is not, since for example in cartesian coordinates, x,y,and z can themselves be functions of time. In spherical and cylindrical coordinates, even the unit vectors depend on time? Also the partial derivative of a curl in curvilinear coordinates is commutative?
 
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  • #2
I think you are confusing coordinate variables (which are usually called x, y, z, t) with position variables (which are also usually called x, y, z, t). The difference is that coordinate variables refer to a fixed grid over which a vector field is defined, and position variables refer to some dynamic position of some object.

A field has a value at each coordinate position, whereas an object only occupies a particular subset of coordinate positions. The time derivative and curl are commutative since they are operations on a field, and the field coordinates are (typically) orthogonal. It doesn't make sense to take the curl of an object position.
 

Related to Taking the time derivative of a curl

1. What is the definition of a curl?

The curl of a vector field is a mathematical operation that measures the rotation of the field at a given point. It is represented by the symbol ∇ x or curl(∇).

2. Why is it important to take the time derivative of a curl?

Taking the time derivative of a curl helps to analyze the change in rotation of a vector field over time. It is especially useful in physics and engineering applications, such as fluid dynamics and electromagnetism.

3. How do you calculate the time derivative of a curl?

The time derivative of a curl can be calculated by taking the curl of the time derivative of the vector field. In other words, you first find the curl of the vector field at a given point and then find the time derivative of that result.

4. What is the physical interpretation of the time derivative of a curl?

The physical interpretation of the time derivative of a curl is the rate of change of rotation of the vector field. This can represent the change in angular velocity or the acceleration of a rotating object.

5. Can the time derivative of a curl ever be zero?

Yes, the time derivative of a curl can be zero in certain cases. This means that the rotation of the vector field is not changing over time, and the field is said to be in a state of steady rotation. This can occur in systems with constant angular velocities or in static systems with no rotation.

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