[SOLVED] System of 2 variables

[anemone]

Solve the system $x^5+y^5=33,\,x+y=3$.

 

[solakis]

Spoiler

$(x+y)^5=x^5+y^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4=33+5xy(x^3+y^3)+10x^2y^2(x+y)=

=33+5xy((x+y)^3-3xy(x+y))+30x^2y^2= 33+5xy(27-9xy)+30x^2y^2=243$
or
$15x^2y^2-135xy+210=0$
or
$x^2y^2-9xy+14=0$
And xy=7 or xy=2 impling the following 2 systems of equations :

x+y=3. (A)
xy=2

x+y=3 (B)
xy=7
And (A) gives (x=1,y=2),(x=2,y=1) (B) has no real solutions

 

[anemone]

Thanks for participating, solakis ! Ah, the question is meant to ask for complex solutions too!

 

[solakis]

Spoiler

$(x+y)^5=x^5+y^5+5x^4y+10x^3y^2+10x^2y^3+5xy^4=33+5xy(x^3+y^3)+10x^2y^2(x+y)=

=33+5xy((x+y)^3-3xy(x+y))+30x^2y^2= 33+5xy(27-9xy)+30x^2y^2=243$
or
$15x^2y^2-135xy+210=0$
or
$x^2y^2-9xy+14=0$
And xy=7 or xy=2 impling the following 2 systems of equations :

x+y=3. (A)
xy=2

x+y=3 (B)
xy=7
And (A) gives (x=1,y=2),(x=2,y=1) (B) has no real solutions

Spoiler

The complex solutions are:
[x=(3+i$\sqrt 19$)/2, y=(3-i$\sqrt 19$)/2]............[x=(3-i$\sqrt 19$)/2 , y=( 3+i$\sqrt 19$)/2]