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#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

I got problem understanding how they can do this.

\(\displaystyle \int_0^1\int_x^1 \sin(y^2)dydx\)

and rewrite it as \(\displaystyle \int_0^1\int_0^y \sin(y^2) dxdy\)

What I have done is.

Then function is continuous (\(\displaystyle \sin\) is a trig function) on a type I region D.

We got \(\displaystyle D= (x,y)| 0\leq x \leq 1, x \leq y \leq 1\)

Regards,