Suppose T is a linear map and dim(Im(T))=k

In summary, a linear map is a mathematical function that preserves the operations of addition and scalar multiplication. The significance of dim(Im(T))=k is that it tells us the size and structure of the image of the linear map. The dimension of the image is also related to the rank of the linear map, as they both have a value of k if dim(Im(T))=k. A linear map can have a dimension of 0, meaning the image is the zero vector. The dimension of the image is also related to the nullity of the linear map, as the nullity is n-k if dim(Im(T))=k.
  • #1
mivanova
7
0
Please, help me!
Suppose T is a linear map and dim(Im(T))=k. Prove that T has at most k+1 distinct eigenvalues.
Thank you in advance!
 
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  • #2


If T maps an n dimensional space into an m dimensional space, then the kernel of T must be of dimension n- k. And, of course, every vector in the kernel of T is an eigenvector with eigenvalue 0. Now, since each eigenvalue has a corresponding "eigen"space of dimension at least 1, how many other eigenvalues can there be?
 

Related to Suppose T is a linear map and dim(Im(T))=k

1. What does it mean for a map to be linear?

A linear map is a mathematical function or transformation that preserves the operations of addition and scalar multiplication. In other words, the output of a linear map when applied to a linear combination of inputs will be the same as the linear combination of the outputs of the map applied to each individual input.

2. What is the significance of dim(Im(T))=k?

The dimension of the image (Im) of a linear map T refers to the number of linearly independent vectors in the range of the map. In this case, dim(Im(T))=k means that the image has a basis of k linearly independent vectors. This is important because it tells us the size and structure of the image of the linear map.

3. How is the dimension of the image related to the rank of a linear map?

The rank of a linear map T is defined as the dimension of the image of T. Therefore, if dim(Im(T))=k, then the rank of T is also k.

4. Can a linear map have a dimension of 0?

Yes, a linear map can have a dimension of 0. This means that the image of the map is the zero vector (or the trivial vector space). In other words, the map is not able to map any vectors to a nonzero output.

5. How does the dimension of the image relate to the nullity of a linear map?

The nullity of a linear map T is defined as the dimension of the kernel (null space) of T. The null space is the set of all vectors that are mapped to the zero vector by T. Therefore, if dim(Im(T))=k, then the nullity of T is n-k, where n is the dimension of the domain of T.

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