- #1
smoger
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I'm confused about the superposition when the B.C(boundary condition) is continuity condition between two domain.
The laplace equation(or possion) expressed as (in circular annulus),
∂2A/∂r2 + 1/r ∂A/∂r + 1/r2 ∂2A/∂θ2 = f(r,θ)
Assume that there are two domains where the boundary of each domain is :
1. (a<r<b, 0<θ<2pi)
with B.C : A1(b,θ)=A2(b,θ) , and etc.. on elsewhere(r=a, or θ=somewhere)
2. (b<r<c, 0<θ<2pi)
with B.C : ∂A1/∂θ=∂A2/∂θ (at r=b)
, and etc.. on elsewhere(r=c, or θ=somewhere)
Is that right to solve the equation by adopting super position theory?
for example, In domatin 1,
A1(r,θ)=A11(r,θ)+A12(r,θ) (1)
that,
A11(r,θ) satisfy A11(b,θ)=0 (2)
A12(r,θ) satisfy A12(b,θ)=A2(b,θ) (3)
Can i make the continuty condition 0 as a general non homogeneous B.C condition to solve the equation by
super position? thanks in advance
The laplace equation(or possion) expressed as (in circular annulus),
∂2A/∂r2 + 1/r ∂A/∂r + 1/r2 ∂2A/∂θ2 = f(r,θ)
Assume that there are two domains where the boundary of each domain is :
1. (a<r<b, 0<θ<2pi)
with B.C : A1(b,θ)=A2(b,θ) , and etc.. on elsewhere(r=a, or θ=somewhere)
2. (b<r<c, 0<θ<2pi)
with B.C : ∂A1/∂θ=∂A2/∂θ (at r=b)
, and etc.. on elsewhere(r=c, or θ=somewhere)
Is that right to solve the equation by adopting super position theory?
for example, In domatin 1,
A1(r,θ)=A11(r,θ)+A12(r,θ) (1)
that,
A11(r,θ) satisfy A11(b,θ)=0 (2)
A12(r,θ) satisfy A12(b,θ)=A2(b,θ) (3)
Can i make the continuty condition 0 as a general non homogeneous B.C condition to solve the equation by
super position? thanks in advance
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