- #1
tandoorichicken
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This was an extra credit problem on our last test. We haven't learned how to do it yet but I was just curious as to how it would be done.
[tex]\int^{x^2}_{5} \sqrt{1 + t^2} \,dt = G(x) [/tex]
Find G'(x).
[tex]\int^{x^2}_{5} \sqrt{1 + t^2} \,dt = G(x) [/tex]
Find G'(x).