Sturm Liouville and Self Adjoint ODEs

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In summary, the Sturm-Liouville form of a second-order differential equation is a special form that can be written as a(x)y′′ + b(x)y′ + c(x)y = λρ(x)y, where a(x), b(x), and c(x) are continuous functions, λ is a constant, and ρ(x) is a weight function. Self-adjointness in Sturm-Liouville equations refers to the property that the differential operator in the equation is equal to its adjoint operator, making it easier to find and analyze the solution. The Sturm-Liouville theory relates to eigenvalue problems, allowing for the use of eigenvalue techniques to solve the equation and determine the eigenvalues and eigenfunctions
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Ed Quanta
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So how do I show that when we have a linear second-order differential equation expressed in self adjoint form that the Wronskian W(y1,y2)= C/p(x)

W=y1y2'-y1'y2, and C is a constant, and p is the coefficient where Ly=d^2/dx^2(pu) - d/dx(p1u) +p2u ?

I know Ly1=0 and Ly2= 0 if that helps at all.
 
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why don't you start by writting down the definition for self-adjointness?

then take [itex](Ly,u)[/itex] and integrate by parts.
 
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To show that the Wronskian of two solutions of a self-adjoint linear second-order differential equation is a constant multiple of the coefficient p(x), we can use the Sturm-Liouville theorem. This theorem states that for a self-adjoint differential equation of the form Ly = d^2/dx^2(pu) - d/dx(p1u) +p2u, the Wronskian W(y1,y2) = C/p(x) where C is a constant, if and only if y1 and y2 are solutions to the differential equation and satisfy the boundary conditions y1(a) = y2(a) = 0.

In this case, since we are given that Ly1 = 0 and Ly2 = 0, we can use the Sturm-Liouville theorem to conclude that the Wronskian of y1 and y2 is a constant multiple of p(x). This is because the boundary conditions y1(a) = y2(a) = 0 imply that y1 and y2 are linearly independent solutions, and thus their Wronskian is non-zero. The Sturm-Liouville theorem then tells us that the Wronskian is a constant multiple of p(x), which is what we wanted to show.

To further understand this result, we can also consider the physical interpretation of the Wronskian in the context of the self-adjoint differential equation. The Wronskian represents the rate of change of the solutions y1 and y2 with respect to each other. In a self-adjoint differential equation, the coefficient p(x) represents the density of a physical system, and the solutions y1 and y2 represent different modes of vibration. So, the Wronskian being a constant multiple of p(x) means that the rate of change of these different modes of vibration is directly proportional to the density of the system, which is a physically intuitive result.

In summary, we can show that the Wronskian of two solutions of a self-adjoint linear second-order differential equation is a constant multiple of the coefficient p(x) by using the Sturm-Liouville theorem and the boundary conditions given in the problem. This result has a physical interpretation in terms of the density and modes of vibration of the system.
 

Related to Sturm Liouville and Self Adjoint ODEs

1. What is the Sturm-Liouville form of a second-order differential equation?

The Sturm-Liouville form of a second-order differential equation is a special form that can be written as:
(a(x)y')' + b(x)y' + c(x)y = λρ(x)y
where a(x), b(x), and c(x) are continuous functions, λ is a constant, and ρ(x) is a weight function.

2. What is the significance of self-adjointness in Sturm-Liouville equations?

In Sturm-Liouville equations, self-adjointness refers to the property that the differential operator in the equation is equal to its adjoint operator. This means that the solution to the equation will satisfy certain orthogonality and completeness conditions, making it easier to find the solution and analyze its properties.

3. How does the Sturm-Liouville theory relate to eigenvalue problems?

The Sturm-Liouville form of a second-order differential equation can be written as an eigenvalue problem, where the eigenvalues are the constants λ and the eigenfunctions are the solutions y(x). This allows for the use of eigenvalue techniques to solve the equation and determine the eigenvalues and eigenfunctions.

4. Can Sturm-Liouville equations be solved analytically?

Yes, some Sturm-Liouville equations can be solved analytically using special functions such as Bessel functions or Legendre polynomials. However, in many cases, numerical methods are required to find the solution.

5. What are some real-world applications of Sturm-Liouville equations?

Sturm-Liouville equations have many applications in physics, engineering, and other fields. They can be used to model physical phenomena such as heat transfer, fluid flow, and quantum mechanics. They are also used in signal processing, image processing, and data analysis.

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