Stupid question on the qed renormalization

In summary, the conversation discusses the concept of renormalization in theoretical physics and its impact on calculating observables such as cross sections. It is explained that at tree level, the "bare" and renormalized parameters are equivalent, but at higher orders, the introduction of new "renormalized" parameters is necessary to account for infinities in Green functions. This results in a need to re-express the cross section in terms of these renormalized parameters. The conversation also mentions the importance of considering higher order perturbations and the effects on parameters like charge.
  • #1
paolorossi
24
0
I did not understand one thing: imagine we have calculated a cross section relates to a process, for example compton scattering. The parameters (charge, mass, ...) that come into play in cross section are "bare parameters"? Then after the renormalization of the theory, getting the "bare parameters" in terms of "physical parameters", we must re-express the cross section calculated in terms of "physical parameters"?
 
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  • #2
It depends on what order are you calculating the cross section. If you are working on tree level then the "bare" parameters coincide with the renormalized one (at that particular order of perturbation theory).
On the other hand, if you want to work at higher orders then some inifinities arise. This means that Green functions are infinite. So you have to redefine you theory with new "renormalized" parameters in order to obtain finite Gree functions. So, in higher orders the observables (like differential cross section), which are contructed over Green functions, are directly created via renormalized finite parameters.
 
  • #3
this is evident if we consider processes of second order perturbation, in fact, being the differences between bare and renormalized parameters of the second order, for example for charge
Code:
e[SUB]phys[/SUB] = e[SUB]bare[/SUB] + O(e[SUB]bare[/SUB] [SUP]2[/SUP])

these be to undermine the terms of the development of higher-order... now beginning to understand, thanks

----

but what happens to subsequent orders?
 

Related to Stupid question on the qed renormalization

1. What is the qed renormalization?

The qed renormalization is a mathematical technique used in quantum electrodynamics (qed) to remove infinities and make predictions about the behavior of subatomic particles. It is an important tool for understanding the fundamental forces of nature.

2. Why is the qed renormalization necessary?

The qed renormalization is necessary because the equations in qed, which describe the interactions between particles, can produce infinite values. These infinities do not have physical meaning and need to be removed in order to make accurate predictions.

3. How does the qed renormalization work?

The qed renormalization works by introducing a cut-off value or "renormalization scale" to limit the calculations to a certain energy range. By adjusting this scale, the infinities can be cancelled out and the calculations can produce finite, meaningful results.

4. Are there any limitations to the qed renormalization?

Yes, there are limitations to the qed renormalization. It is only applicable to certain types of quantum field theories, and it can become increasingly complex and difficult to apply in higher-order calculations. In some cases, alternative methods may need to be used.

5. What are some real-world applications of the qed renormalization?

The qed renormalization has been successfully used in predicting and explaining a wide range of phenomena, such as the magnetic moment of the electron, the Lamb shift in atomic spectra, and the anomalous magnetic dipole moment of the muon. It is also used in the development of new technologies, such as the Standard Model of particle physics and quantum computing.

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