Stress tensor transformation

In summary, when reducing the stiffness matrix from 21 to 13 coefficients, it is necessary to assume one plane of material symmetry. This requires transforming from a right-handed coordinate system to a left-handed coordinate system, as the stress and strain components are invariant under rotations in the same handedness. This transformation is necessary in order to correctly zero out certain coefficients of the stiffness matrix and result in 13 coefficients.
  • #1
tricha122
20
1
Hi all,

I have been reading up about continuum mechanics recently, and have a question regarding the reduction in stiffness coefficients in the stiffness matrix.

I am aware of how the stiffness matrix is reduced to 21 coefficients. However, in order to reduce it from 21 to 13, one has to assume 1 plane of material symmetry.

When doing so, (say x1 = 0 is the plane of symmetry), in order to reduce the # of coefficients, you have to look at sigma = C*epsilon, and sigma' = C'*epsilon'

where C = C' for 1 symmetric plane.

Transforming sigma and epsilon from OX1X2X3 to OX1'X2X3 you can get the "boundary conditions" you need to zero out certain coefficients of the stiffness matrix and result with 13 (from 21).

My problem is O-X1-X2-X3 to O-X1'-X2-X3 is changing from a RH coordinate system to a LH coordinate system.

a RH to RH system would look like this: O-X1-X2-X3 to O-X1'-X2'-X3.

However, when i attempt the same reduction with that transformation the math doesn't work out correctly.

SHould it work out? Does one always use a RH->LH transformation when using planes of symmetry?

Any help would be greatly appreciated.

Thanks
 
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  • #2
!</code>Yes, the transformation you are using is correct. The transformation from a right-handed coordinate system to a left-handed coordinate system is necessary when dealing with plane symmetry. This is because of the way in which the stress and strain components transform under rotations. The components of stress and strain are always invariant under rotations in the same handedness. Therefore, if we have a right-handed coordinate system, then when we rotate it by 180 degrees (which would be the plane of symmetry for plane strain problems), the stress and strain components would remain the same.However, if we rotate it by 180 degrees in a left-handed coordinate system, the stress and strain components will no longer remain the same. Therefore, we need to use the left-handed coordinate system to properly account for the plane of symmetry. Hope this helps!
 

Related to Stress tensor transformation

1. What is a stress tensor transformation?

A stress tensor transformation is a mathematical process that is used to convert stress tensors from one coordinate system to another. This allows for the analysis of stress and strain in different directions and orientations.

2. Why is stress tensor transformation important in science?

Stress tensor transformation is important in science because it allows for the accurate analysis and understanding of stress and strain in different materials and structures. This is crucial in fields such as engineering, materials science, and geology.

3. What are the different types of stress tensor transformations?

There are two main types of stress tensor transformations: rotation and coordinate transformation. Rotation transformations are used when the coordinate system changes orientation, while coordinate transformations are used when the coordinate system itself changes.

4. How is stress tensor transformation calculated?

Stress tensor transformation is calculated using mathematical equations that take into account the orientation and direction of the stress tensor in relation to the new coordinate system. These equations involve matrix multiplication and trigonometric functions.

5. Can stress tensor transformation be applied to all materials?

Yes, stress tensor transformation can be applied to all materials, as long as the material behaves in a linear manner under stress. This means that the material's response to stress is proportional to the applied stress and does not exhibit plastic deformation.

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