Strange physics question involving no constants and all variables.

Hint 3: v(t) = Kt + DHint 4: d(t) = K^2t^2/2 + Dt + EIn summary, we are given the time derivative of acceleration, K, and asked to find the functions for acceleration, velocity, and displacement. Using the fundamental theorem of calculus, we can find these functions by taking the integral of K with respect to time. The resulting functions are a(t) = K^2/2 + C, v(t) = Kt + D, and d(t) = K^2t^2/2 + Dt + E. We can also show that af^2 = ao^2 + 2J(Vf-Vo)
  • #1
TexasCow
40
0

Homework Statement


"K" is the time derivative of acceleration. Assume initial conditions of Ao, Vo, and Do.("o"=initial).

Find:
a(t):
v(t):
d(t):

Show that:
af^2=ao^2+2J(Vf-Vo)


Homework Equations



I'm honestly lost on this one..I don't know where to start. I could probably do it with numbers but clueless with variables!



The Attempt at a Solution

 
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  • #2
Hey,

Remember that what is common between the: displacement, velocity, and acceleration functions; are that they're all functions of time, indicating that [itex]t[/itex] is your only variable.

Therefore, consider the following,

[tex]
{\frac{d}{dt}}{\left[a(t)\right]} = K
[/tex]

So, if the derivative with respect to [itex]t[/itex] was taken to get K, how do you get back [itex]a(t)[/itex]?

Once you figure that out repeat for [itex]v(t)[/itex] and [itex]d(t)[/itex].

Thanks,

-PFStudent
 
Last edited:
  • #3
Hint: Use the Fundamental Theorem of Calculus.
 
  • #4
Integral maybe?
 
  • #5
TexasCow said:
Integral maybe?

Hey,

Yes. To get you started here is how it looks,

[tex]
{a(t)} = {\int_{}^{}}{K}{dt}
[/tex]

Thanks,

-PFStudent
 
  • #6
Well we haven't gotten there in calc yet but I'm sure I can find out how to do that online somewhere.
 
  • #7
Hint 1: K is the same as K^1
Hint 2: a(t) = K^2/2 + C
 

Related to Strange physics question involving no constants and all variables.

1. What is meant by "strange physics" in this context?

"Strange physics" refers to any phenomenon or theory that goes against our current understanding of the laws of physics. It may involve concepts such as time travel, parallel universes, or non-locality.

2. Can a physics question have no constants and all variables?

Yes, a physics question can have no constants and all variables. This means that all values in the equation are unknown and need to be solved for in order to find a solution. This type of question is commonly seen in advanced physics problems or theoretical physics.

3. How do scientists approach solving a physics question with no constants and all variables?

Scientists typically use mathematical models and equations to analyze and solve these types of questions. They may also use experimental data to support their conclusions or develop new theories.

4. Can strange physics theories be proven or disproven?

It is difficult to definitively prove or disprove strange physics theories due to the complex and often abstract nature of these concepts. However, scientists can use evidence and experiments to support or refute these theories.

5. Are there any real-world applications for strange physics theories?

While some strange physics theories may seem purely theoretical, they can actually have real-world applications. For example, the theory of non-locality has been applied to the development of quantum computers and the concept of time dilation has practical applications in GPS technology.

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