- Feb 22, 2012
^ I had to copy in the question as an img because I don't know how to tex some of the symbols. Hope this is ok...
Basically my understanding of this question is that it doesn't make sense? How can you have crossproduct with an integral operator?
This result looks similar to the definition of Stokes' theorem but it is not quite exact so... does any one know if this even make sense or what am I seeing wrong?
As for the 'second' part of the question, should I just do line integral and surface integral and then compare result to show equality?
The way I see it the whole thing doesnt make sense since you cant cross a scalar function...
what does crossproduct with dS even mean? Is that going to be (d/dx, d/dy, d/dz)? I can do that if so but I don't know that I would be doing the right thing. Either way I dont know how Stokes Theorem can be used to show this relationship because the function is a scalar not vector..