Static Equilibrium of pedestals

In summary, the problem involves a diver of weight 730 N standing on a diving board of length 5 m and negligible mass fixed to two pedestals separated by distance 1.5 m. The task is to determine the magnitude and direction of the force on the board from the left pedestal, with upward being taken as positive. Using the sum of forces in the y direction, two equations are set up and solved for the unknown forces (Fl and Fr). The solution is on the right track.
  • #1
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Homework Statement


A diver of weight 730 N stands at the end of a diving board of length L = 5 m and negligible mass. The board is fixed to two pedestals separated by distance d = 1.5 m.

What are the magnitude and direction of the force on the board from the left pedestal? (Include the sign. Take upward to be positive.)


Homework Equations


I think that it's this..

sum of forces in the y direction = 0

force of left pedestal = Fl
force of right pedestal = Fr
force of diver = mg = 730N



The Attempt at a Solution



-Fl + Fr - mg = 0
3.5Fr(mg) - (0)mg = 5Fl(mg)

is this on the right track?
 
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  • #2
Looks good! You have 2 equations with 2 unknowns so you can find the answer.
 
  • #3


Your approach is on the right track. However, in order to find the magnitude and direction of the force on the board from the left pedestal, we need to consider the torque acting on the board as well.

First, let's label the forces acting on the board: the force from the left pedestal as Fl, the force from the right pedestal as Fr, and the weight of the diver as mg.

Next, we can set up the equation for torque:

sum of torques = 0

In this case, we can choose the pivot point to be at the left pedestal. This means that the torque from the force of the right pedestal will be negative (since it is trying to rotate the board in the opposite direction) and the torque from the weight of the diver will be positive (since it is trying to rotate the board in the same direction).

Therefore, our equation becomes:

-Fl(d) + Fr(d) + mg(L/2) = 0

Solving for Fl, we get:

Fl = (Fr + mg(L/2))/d

Plugging in the given values, we get:

Fl = (0 + 730(5/2))/1.5 = 1216.67 N

The magnitude of the force on the board from the left pedestal is 1216.67 N and its direction is upward (positive).

This result makes sense because the left pedestal is supporting more weight (due to the weight of the diver and the torque from the weight) compared to the right pedestal. This is necessary for the board to remain in static equilibrium.
 

Related to Static Equilibrium of pedestals

What is static equilibrium?

Static equilibrium is a state in which an object is at rest and all forces acting on it are balanced, resulting in zero net force and zero net torque.

What is the importance of static equilibrium in pedestals?

Static equilibrium is crucial in pedestals because it ensures stability and prevents the pedestal from tipping over. Without static equilibrium, the pedestal would be unstable and unable to support the weight of the object on top.

How is static equilibrium achieved in pedestals?

Static equilibrium in pedestals is achieved by ensuring that the center of mass of the pedestal and the object on top are directly above the base of the pedestal. Additionally, the weight of the pedestal and the object must be evenly distributed around the base to prevent any imbalance.

What factors can affect static equilibrium in pedestals?

The weight and distribution of the object on top, the shape and size of the pedestal, and external forces such as wind or vibrations can all affect static equilibrium in pedestals. Any changes to these factors can disrupt the balance and stability of the pedestal.

How can static equilibrium be maintained in pedestals?

To maintain static equilibrium in pedestals, it is important to regularly check and adjust the weight and distribution of the object on top, as well as ensuring the base of the pedestal is stable and on a level surface. In cases of external forces, additional measures such as anchoring the pedestal may be necessary.

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