Stability Condition for Circular Orbit

In summary, the stability condition for a circular orbit of radius a is equivalent to the condition for the second derivative of the effective potential to be greater than zero at r=a. This can be seen by rewriting the first condition in terms of the potential and noting the similarities with the second condition.
  • #1
cpburris
Gold Member
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Homework Statement



Show that the stability condition for a circular orbit of radius a, i.e.

[itex]f(a) + \frac{a}{3} (\frac{df}{dr})_{r=a} < 0 [/itex]

is equivalent to the condition

[itex] \frac{d^2V(r)}{dr^2} > 0 [/itex]

for r=a where V(r) is the effective potential given by

[itex] V(r) = U(r) + \frac{ml^2}{2r^2} [/itex]

The Attempt at a Solution



I understand fully why they are equivalent, and I would have no problem proving individually how each is a condition for stability, but analytically I really don't know how to show the two are equivalent. I'm not even sure what the question is asking. I tried just setting

[itex] -\frac{d^2V(r)}{dr^2} = f(a) + \frac{a}{3} (\frac{df}{dr})_{r=a} [/itex]

and do something from there, but it didn't get me anywhere.
 
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  • #2
I'm guessing that you already know what ##f(r)## is as a function of the potential? So if you use this definition, you could write out ##f(a) + \frac{a}{3} (\frac{df}{dr})_{r=a} < 0## in terms of the potential instead, and start to see how it could be similar to the other equation.
 

Related to Stability Condition for Circular Orbit

What is the Stability Condition for Circular Orbit?

The Stability Condition for Circular Orbit is a mathematical principle used to determine whether a celestial body will maintain a circular orbit around a central object. It takes into account the mass and velocity of the orbiting body, as well as the gravitational force between the two objects.

How is the Stability Condition Calculated?

The Stability Condition is calculated using the formula GM/r^2 > v^2, where G is the gravitational constant, M is the mass of the central object, r is the distance between the two objects, and v is the velocity of the orbiting body. If this condition is met, the orbit will be stable.

What Happens if the Stability Condition is Not Met?

If the Stability Condition is not met, the orbit will not be stable and the orbiting body will eventually deviate from its circular path. This could result in the body either crashing into the central object or being flung out into space.

Can the Stability Condition Change?

Yes, the Stability Condition can change depending on the variables involved. For example, if the mass of the central object or the velocity of the orbiting body changes, the Stability Condition will also change.

How is the Stability Condition Used in Space Exploration?

The Stability Condition is an important factor to consider when planning space missions. It helps scientists and engineers determine the necessary velocities and trajectories for spacecrafts to maintain stable orbits around planets or other celestial bodies. It is also used to predict and avoid potential collisions between orbiting bodies.

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