# Squeeze Theorem

#### Albert Einstein

##### New member
I am not entirely sure if I solved this problem correctly. Please let me know if my reasoning is flawed. Thank you and I appreciate your help greatly.

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#### Prove It

##### Well-known member
MHB Math Helper
The function is continuous, just substitute x = 0...

#### Prove It

##### Well-known member
MHB Math Helper
On second thought, I didn't read the question properly... Please disregard my previous post.

#### Country Boy

##### Well-known member
MHB Math Helper
The function IS continuous at x=0 but you need to show that $\lim_{x\to 0} f(x)= 1$ to show THAT so continuity cannot be used to do this exercise.

Albert, you state that $-1\le x^2- 2\le 1$. That is the same as $1\le x^2\le 3$. If x is close to 0 that is NOT true! You also have $\lim_{x\to 0} -x^2= 1$ and $\lim_{x\to 0} x^2= 1$. Those are certainly not true! Did you mean "= 0"?