- #1
ilp89
- 17
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Could someone demonstrate to me how in Landau's Mechanics book, he gets from equation (16.5)
tan θ = (v_0 sin θ_0) / (v_0 cos θ_0 + V)
to equation (16.6)
cos θ_0 = -(V/v_0) sin^2 θ ± cos θ √[1 - (V/v_0)^2 sin^2 θ]
I am using the quadratic formula, and the first term on the right comes out fine, but I can't get the second term.
Thanks!
tan θ = (v_0 sin θ_0) / (v_0 cos θ_0 + V)
to equation (16.6)
cos θ_0 = -(V/v_0) sin^2 θ ± cos θ √[1 - (V/v_0)^2 sin^2 θ]
I am using the quadratic formula, and the first term on the right comes out fine, but I can't get the second term.
Thanks!