Speed of the second hand of a smoothly running analog watch?

[akoma714]

(a) What is the angular speed of the second hand of a smoothly running analog watch?
____ (rad/s)

i got 0.03 pi
webassign says "Check the syntax of your response"
i also tried 0.03, but it's wrong also..

how do i put my answer?

 

[chaoseverlasting]

In radians. pi=180 radians, so 0.03pi= 0.03*180=5.4 radians.

 

[chaoseverlasting]

But, w=theta/t=360/60=6 radians/second.

 

[akoma714]

hmm, those were all wrong.. i don't know

 

[mbrmbrg]

But, w=theta/t=360/60=6 radians/second.

I believe that gives you 6 degrees per second, which still needs to be converted into radians. There are [tex] 2 \pi[/tex] radians in a whole circle.

From the fact that when you entered "pi" webassign told you to check your syntax, I assume that this problem will not accept pi as part of an answer--if you get an answer with pi, multiply out!

 

[akoma714]

360deg/1min = 360deg/60sec = 6deg/sec x 1rad/180deg = 0.03 rad/sec?

 

[akoma714]

OH! I get it now..

360deg/60sec x 2pi rad/360deg = 0.105

Thanks for the help =]

 

[mbrmbrg]

360deg/1min = 360deg/60sec = 6deg/sec x 1pi rad/180deg = 0.03 pi rad/sec?

=(0.0333)*(3.14159...)=_________

edit: you beat me :). Happy physics!
BTW, notice that you multiplied and divided by 360^o. You could have just started working in radians and saved yourself the trouble (but it would have required thinking in new units to begin with).