Speed of light - with observer experiencing gravity

In summary: If the observer on sphere #2 calculates a faster light speed than the observer on sphere #3, then that observer would conclude that the gravity on sphere #2 is stronger than the gravity on sphere #3.
  • #1
rcgldr
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This is related to time dilation effect due to strength of gravity, basically GR effect on calculated speed of light.

Two observers, observer#1 on a very large non-rotating sphere, experiencing 1.0g of gravity, observer#2 is a large distance from the sphere, experiencing 0.1g of gravity. Both observers have identical clocks, and it is known that #1's clock's rate is slower than #2's clock's rate. There are two distant spheres sphere#2, and sphere#3, a large and known distance apart (as measured at 0g while between the two spheres).

A beam of light travels from sphere#2 to sphere#3. If the two observers caclculate the velocity of light based on the known distance versus their local time, they will calculate different velocities.

It seems the only solution to this dilema is if the observed distance between sphere#2 and sphere#3 differs depending on the amount of gravity experienced by an observer, so that observer#1, experiencing 1.0g of gravity, observes a shorter distance between the two distant spheres than observer #2, experincing 0.1g of gravity.
 
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  • #2
Hi Jeff,
I don't know if it's relevant to the answer, but I'll point out that the transverse light beam can't be viewed directly by the observers. Instead, at best they can observe a reflection of the beam, once at the time of emission from sphere #2 and again at the time of arrival at sphere #3. So their perception of sphere #2 - sphere #3 travel time is affected by the additional leg of the trip between each sphere and the observer's location. Observer #1 will see images which are blueshifted compared to what Observer #2 sees although for both observers that will be offset by some redshift depending on the relative masses of the 3 spheres.

Neither observer is in the inertial frame of any portion of the transverse leg of the lightbeam, so I wouldn't think they would have to agree on what they remotely measure to be the speed of light in any such transverse inertial frame.

Jon
 
  • #3
Assume sphere #2 and sphere #3 have very little mass, and are equal distances from both observers.
 

Related to Speed of light - with observer experiencing gravity

1. What is the speed of light?

The speed of light is approximately 299,792,458 meters per second in a vacuum. This is considered to be the fastest speed at which anything can travel in our universe.

2. How does gravity affect the speed of light?

According to Einstein's theory of general relativity, gravity can bend the fabric of space-time. This means that the speed of light can appear to slow down or speed up depending on the strength of the gravitational field it is passing through.

3. Can an observer experiencing gravity perceive the speed of light differently?

Yes, an observer experiencing gravity can perceive the speed of light differently. This is due to the fact that gravity affects the passage of time, as well as the bending of space-time. This means that the perceived speed of light can vary depending on the observer's position in a gravitational field.

4. How does the speed of light change near a massive object?

According to general relativity, the speed of light does not actually change near a massive object. However, the path that light takes can be curved due to the bending of space-time by the object's gravitational field. This can make it appear as though the light is traveling at a slower or faster speed.

5. Is the speed of light constant in all reference frames?

Yes, the speed of light is constant in all reference frames. This is one of the fundamental principles of Einstein's theory of relativity. No matter how fast an observer is moving or how strong the gravitational field they are in, they will always measure the speed of light to be the same.

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