- #1
doaaron
- 65
- 4
Hi all,I originally posted this question as a reply to another post, but afterwards I thought it would be better to start a new thread. Unfortunately, I couldn't figure out how to delete the old post. With that out of the way...
In the experiment, we send either light or sound from a source, and calculate the speed of the wave as (d1 + d0)/(t1 - t0). My understanding is that for light, the calculated speed will be c regardless of v. However, for sound traveling in a stationary medium such as air, its speed in a stationary frame of reference will be independent of v, but the speed calculated by the receiver, (d1 + d0)/(t1 - t0) depends on v.
Am I going wrong somewhere? Earlier, one of the other members mentioned that the speed of sound is independent of the speed of the receiver, just like light.thanks,
Aaron
In the experiment, we send either light or sound from a source, and calculate the speed of the wave as (d1 + d0)/(t1 - t0). My understanding is that for light, the calculated speed will be c regardless of v. However, for sound traveling in a stationary medium such as air, its speed in a stationary frame of reference will be independent of v, but the speed calculated by the receiver, (d1 + d0)/(t1 - t0) depends on v.
Am I going wrong somewhere? Earlier, one of the other members mentioned that the speed of sound is independent of the speed of the receiver, just like light.thanks,
Aaron