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Homework Statement
A proton (mass m = 1.67e-27 kg) is being accelerated along a straight line at 2.4e15 m/s2 in a machine. The proton has an initial speed of 2.4e7 m/s and travels 3.1 cm.
(a) What is its speed?
(b) What is the increase in its kinetic energy?
Homework Equations
V^2 = Vo^2+2ad
KE = 0.5m(Vavg)^2
KE = 0.5m(Vf^2-Vi^2)
The Attempt at a Solution
(a) V^2 = 2.4e7 + 2(2.4e15)(.031)
V^2 = 7.248e14
V = 2.69221e7
(b) KE = 0.5(1.67e-27)((2.69221e7)^2-(2.4e7)^2)
KE = 1.24248e-13