Solving Voltage Capacitors: Step-by-Step Guide

In summary, you need to find the voltage on the upper wire and the voltage on the downside wire, and then subtract them to find the total voltage.
  • #1
FiskiranZeka
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0
Capacitors - Voltage [ Solved ]

Can you explain me the steps of solving this problem and write the process/calculation ?
Thank you very much.
 

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  • #2
FiskiranZeka said:
Can you explain me the steps of solving this problem and write the process/calculation ?
Thank you very much.
Welcome to PF,

That's not the way it works here. We will help you through your homework, but we won't do it for you.

What have you tried thus far?
 
  • #3
You are asking how i treid to solve this right ?
So, i explain;

q=V.C

3C + C --> 4C
q = 4C. V1

On the Upper Wire, there is 10 Voltage
On the Upper Wire, there is Tottal 4C + 1C --> 4/5 C
On the Upper Wire,
Q= 4C.V1 or 4/5C.Vtotal
( Vtotal = 10 Volt )
So, V1= 2 Volt,
V1/V2 = 1/4
So V2=8 Volt,
On the downside Wire,
above Cx is 8 Voltage,
So above 2C must be 2 Voltage, because 2+8 = 10 Volt ( Total Voltage )
q on the downside wire is;
q= V2.Cx or q = 2C. ( Voltage of 2C )
So, V2.Cx = 2C. ( Voltage of 2C )
V2 = 8 Volt,
8.Cx = 2C . 2Volt
Cx = 1/2 is the wrong answer, what i have found...
 
  • #4
FiskiranZeka said:
You are asking how i treid to solve this right ?
So, i explain;

q=V.C

3C + C --> 4C
q = 4C. V1

On the Upper Wire, there is 10 Voltage
On the Upper Wire, there is Tottal 4C + 1C --> 4/5 C
On the Upper Wire,
Q= 4C.V1 or 4/5C.Vtotal
( Vtotal = 10 Volt )
So, V1= 2 Volt,
V1/V2 = 1/4
So V2=8 Volt,
On the downside Wire,
above Cx is 8 Voltage,
So above 2C must be 2 Voltage, because 2+8 = 10 Volt ( Total Voltage )
q on the downside wire is;
q= V2.Cx or q = 2C. ( Voltage of 2C )
So, V2.Cx = 2C. ( Voltage of 2C )
V2 = 8 Volt,
8.Cx = 2C . 2Volt
Everything looks good up until this point. Your next statement is incorrect:
Cx = 1/2
Picking up from your previous like you have:

[tex]8C_x = 4C[/tex]

Hence,

[tex]C_x = \frac{1}{2}{\color{red}\bold{C}}[/tex]

You still need to eliminate the unknown Capacitance (C). Do you follow?
 
  • #5
Yeah sorry,
my calculations say -->
Cx = 1/2 C

But correct answer is Cx = 8C

As the answer has Unknown Capacitance (C) too...
We don't need to eliminate C...
No problem... Just need to find how many C is equal to Cx.
 
  • #6
FiskiranZeka said:
Yeah sorry,
my calculations say -->
Cx = 1/2 C

But correct answer is Cx = 8C

As the answer has Unknown Capacitance (C) too...
We don't need to eliminate C...
No problem... Just need to find how many C is equal to Cx.
After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.

Wherever you got the 'correct' answer of Cx = 8*C is incorrect.
 
  • #7
Hootenanny said:
After discussing this problem with another Homework Helper, we both agree that the correct answer is Cx = 1/2*C as you have.

Wherever you got the 'correct' answer of Cx = 8*C is incorrect.

Yeayy ! Thank you !
I have also doubt that 8C Could be wrong, but i couldn't be sure, 'cos it's Physic Book's answer. Anyway, now I am glad :))

// Problem Solved.
 

Related to Solving Voltage Capacitors: Step-by-Step Guide

1. What is a voltage capacitor?

A voltage capacitor is an electronic component that stores electrical charge and can release it when needed. It consists of two conductive plates separated by an insulating material, and its purpose is to maintain a stable voltage in a circuit.

2. How do I calculate the voltage of a capacitor?

The voltage of a capacitor can be calculated by dividing the charge stored in the capacitor by its capacitance. The formula is V = Q/C, where V is voltage, Q is charge, and C is capacitance. The capacitance of a capacitor is measured in farads (F).

3. What is the step-by-step process for solving voltage capacitors?

The step-by-step process for solving voltage capacitors includes identifying the given values (voltage, capacitance, and charge), using the formula V = Q/C to calculate the missing value, and then verifying the solution by checking if the voltage on the capacitor matches the calculated value.

4. Can I solve for the voltage of a capacitor if I only know the capacitance and charge?

Yes, you can solve for the voltage of a capacitor if you know the capacitance and charge. You can use the formula V = Q/C, where V is voltage, Q is charge, and C is capacitance. Make sure to use consistent units for all values (e.g. volts for voltage, farads for capacitance, and coulombs for charge).

5. How do I know if the voltage on a capacitor is too high or too low?

If the voltage on a capacitor is too high, it can cause damage to the capacitor or the circuit it is connected to. On the other hand, if the voltage is too low, the capacitor may not function properly. It is important to check the voltage on a capacitor and make sure it is within the recommended range for the specific capacitor. If not, steps should be taken to adjust the voltage, such as adding or removing capacitors in a circuit.

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