Solving Thermite Reaction: 1 Mole Al + 10.0g Fe2O3

[chemister]

Please Help!

I am still having problems with this problem...

It deals with the thermite reaction [tex]Fe_{2}O_{3}+2Al----2Fe+Al_{2}O_{3}[/tex]

If 1 mole of Al is reacted with 10.0g of [tex]Fe_{2}O_{3}[/tex], how many grams of unreacted Al would remain?

 

[NateTG]

How many moles of [itex]Fe_2O_3[/itex] are there in 10g?

 

[chemister]

There are about 0.0626 moles of [tex]Fe_{2}O_{3}[/tex] in 10.0g

 

[poolwin2001]

This is a double post.
Anyway no:moles of [itex]Fe_2O_3[/itex] reacted will be twice no:moles of aluminium.
if only 0.0626 moles of [itex]Fe_2O_3[/itex] is present then correspondingly 0.0626*2 moles of Al will react.

 

[archie]

Al remaining

Assuming 10 g of Fe2O3 = 0.0626 moles (too lazy to look at periodic table),
then Al remains is (1 - (2*0.0626))= 0.8748 mol of Al = approx. 23.6 g of Al