Solving the Mystery of a Simple Electronic Circuit's 2V Drop

[momomo_mo]

hi
That's the question.
I have done an experiment.
The voltage of a free DC power supply was set to 5V. When it was connected to a circuit, its voltage dropped to 3V. What happened?

Isn't the 2V is lost in the internal resistance of the power supply.
However,the power supply will continuously supply 5V.So why do the voltage will drop to 3V.And, in a simple circuit,the voltage will be 0V when it comes to the end after passing through those resistance,so why the voltage will drop to 3V.

Thanks everyone!

 

[antonantal]

The voltage drops at the point where you connect the load because a voltage divider is formed of the internal resistance of the supply and the resistance of the load. The voltage drop will be significant if the load has a very low resistance.

 

[m2003]

I would approach this situation by first examining the components of the circuit and their individual resistances. It is possible that the internal resistance of the power supply is causing the 2V drop, but it could also be influenced by the resistances of other components in the circuit. I would also consider the overall design and layout of the circuit, as well as any potential sources of interference or fluctuations in the power supply. Additionally, I would perform further experiments and measurements to gather more data and analyze the results to determine the cause of the 2V drop. This type of investigation and analysis is crucial in solving mysteries in science and can lead to a better understanding of electronic circuits and their behavior.