Solving Simple Work Problem: 515J

In summary, the problem involves a 70.0 kg sailor climbing an 11.5 m long rope ladder to a mast at a constant velocity. The ladder is at an angle of 30.0° with the mast and is assumed to be frictionless. Using the equation W = Fd, the sailor's work can be calculated by finding the net force parallel to the ladder, which is equal to the applied force minus the force of gravity. The work is then calculated by multiplying this net force by the distance climbed, resulting in a value of 515 J. However, the solution manual indicates that this is not the correct answer, likely due to the incorrect use of the angle θ, which should be measured with respect to
  • #1
Mr Davis 97
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Homework Statement


A 70.0 kg sailor climbs an 11.5 m long rope ladder to a mast above at constant velocity. The rope ladder is at an angle of 30.0° with the mast. Assume that the ladder is frictionless. How much work does the sailor do?

Homework Equations


##W = Fd##

The Attempt at a Solution


[/B]
##F_{net||} = F_{a} + F_{g||}##
##F_{a} = -F_{g} = -mg\sin \theta##
##W = F_{a}d##
##W = -mgd\sin \theta##
##W = -(70kg)(-9.8m/s^{2})(11.5m)0.5##
##W = 515 J##

However, in the solution manual, this is not the correct answer. What am I doing wrong?
 
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  • #2
Mr Davis 97 said:

Homework Statement


A 70.0 kg sailor climbs an 11.5 m long rope ladder to a mast above at constant velocity. The rope ladder is at an angle of 30.0° with the mast. Assume that the ladder is frictionless. How much work does the sailor do?

Homework Equations


##W = Fd##

The Attempt at a Solution


[/B]
##F_{net||} = F_{a} + F_{g||}##
##F_{a} = -F_{g} = -mg\sin \theta##
##W = F_{a}d##
##W = -mgd\sin \theta##
##W = -(70kg)(-9.8m/s^{2})(11.5m)0.5##
##W = 515 J##

However, in the solution manual, this is not the correct answer. What am I doing wrong?
The angle, θ, that you used is with respect to the deck, so it's not 30° .

That is to say, if you use sin(θ) that is with respect to the deck.
 
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Related to Solving Simple Work Problem: 515J

1. What is a simple work problem?

A simple work problem is a type of mathematical problem that involves calculating the amount of work done by a person or machine in a given amount of time. It typically involves using the formula: work = force x distance.

2. What does "515J" stand for in this problem?

515J is the unit for work, specifically joules. Joules are a unit of energy that is commonly used in physics and other sciences.

3. How do you solve a simple work problem?

To solve a simple work problem, you need to first identify the known variables, such as force and distance, and plug them into the formula work = force x distance. Then, you can calculate the work done by multiplying the force and distance values together.

4. Can you give an example of a simple work problem?

Sure! Let's say a person uses a force of 50 newtons to push a box a distance of 10 meters. To calculate the work done, we can use the formula work = force x distance. So, work = 50 newtons x 10 meters = 500 joules.

5. What are some real-life applications of simple work problems?

Simple work problems can be applied to many real-life situations, such as calculating the work done by a person lifting weights at the gym, the work done by a car engine to move a vehicle, or the work done by a person pushing a shopping cart through a store. They are also useful in understanding the concept of energy and how it is transferred and transformed in various systems.

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