Solving Resonance Problem in Air Columns

[insertnamehere]

Problem with Standing Waves in Air Columns

Hello, I'm having problems with this problem, lol...so far, i have found one of the main components of the following question, but I don't know where to go from there. please help

Water is pumped into a tall vertical cylinder at a volume flow rate R. The radius of the cylinder is r, and at the open top of the cylinder a tuning fork is vibrating with a frequency f. As the water rises, how much time elapses between successive resonances?

Ok, so far, this is what I got. I consider R to be V (volume) and since volume of a cylinder is pi(r^2)h where h is the height and equal to L. And since this considers harmonics, L= (wavelength)/4, therefore f= (V speed of sound)/(4L)
So I replaced L with (Volume/area of base or R/(pi*r^2) and solved to find frequency. But i don't know where to go about finding the TIME ELAPSED!
Please help. Thank you

 

[insertnamehere]

Please Helpp!

 

[insertnamehere]

Pleasseeee!

 

[mukundpa]

The water is rising in the cylinder which is behaving as a resonance column(closed organ pipe). With the rise in the level of water the length of air column is decreasing at a rate of [tex] \frac {R}{ \pi r^2} [/tex] m/sec.

For the resonance to occur in the closed organ pipe the lengths of the air column should be [tex] (2n + 1) \frac {\lambda}{4} [/tex]
hence the difference in the lengths for successive resonance is [tex] \frac {\lambda}{2}[/tex]

So find the interval for which water rises by [tex] \frac {\lambda}{2}[/tex]