Solving Redox Reactions: MnCl2 & Cr2O72-

This is an example of a redox reaction where chromium is being reduced from a +6 to a +3 oxidation state. In summary, for the first problem, the chemical equation at the cathode is 2H+ + 2e --> H2 and the reaction is an oxidation-reduction reaction. For the second problem, the half cell is Cr3+|Cr2O72- and the reaction involves chromium being reduced from a +6 to a +3 oxidation state.
  • #1
zorro
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Homework Statement



I have two problems-

1) Given the cell-
Mn(s)|MnCl2(c1)|HCL(c2)|O2(p atm)|Pt

How do we write the chemical equation taking place at cathode?

Is it H2O ------> 2e + 2H+ + 0.5O2 ?
How do we identify the reaction?

2) Write the half cell involving the reaction -

Cr2O72-(aq) + 14H+ + 6e ------> 2Cr3+ + 7H2O

I think it will be Cr2O72-|Cr3+

Any help appreciated.
 
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  • #2
Homework Equations The Attempt at a Solution1) The chemical equation taking place at the cathode is 2H+ + 2e --> H2. This is an oxidation-reduction reaction, commonly referred to as a redox reaction.2) The half cell involving the reaction is Cr3+|Cr2O72-.
 

Related to Solving Redox Reactions: MnCl2 & Cr2O72-

1. How do I balance a redox reaction involving MnCl2 and Cr2O72-?

The first step in balancing a redox reaction is to determine the oxidation states of each element in the reaction. In this case, Mn has an oxidation state of +2 and Cr has an oxidation state of +6. Next, balance the elements that are not involved in the redox reaction. In this case, there are 2 Cl atoms on the reactant side and 7 O atoms on the product side. To balance these, add 2 HCl to the product side and 7 H2O to the reactant side. Finally, balance the elements involved in the redox reaction. Start with one element at a time and use the half-reaction method to balance the charges. Once all elements are balanced, double-check to make sure that the number of atoms on each side is equal.

2. What is the oxidation number of Mn in MnCl2?

In MnCl2, the oxidation number of Mn is +2. This is because Cl has an oxidation number of -1 and there are two Cl atoms, making the total charge -2. Since the overall charge of MnCl2 is neutral, Mn must have an oxidation number of +2 to balance out the negative charge from the Cl atoms.

3. How do I know which element is being oxidized and which is being reduced in a redox reaction?

In a redox reaction, the element that is being oxidized is losing electrons, while the element that is being reduced is gaining electrons. To determine which is which, look at the oxidation states of each element before and after the reaction. If the oxidation state increases, the element is being oxidized. If the oxidation state decreases, the element is being reduced.

4. Can I use the half-reaction method to balance redox reactions with multiple elements?

Yes, the half-reaction method can be used to balance redox reactions with multiple elements. Start by balancing the elements that are not involved in the redox reaction, then balance the elements involved in the redox reaction one at a time using the half-reaction method. It may require multiple iterations to balance all elements in the reaction.

5. What are some common mistakes when balancing redox reactions?

Some common mistakes when balancing redox reactions include forgetting to include all elements involved in the reaction, forgetting to multiply coefficients by the appropriate number, and not checking to make sure that the number of atoms on each side is equal. It is also important to double-check the oxidation states of each element to ensure they are correct before balancing the reaction.

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