- #1
Bassalisk
- 947
- 2
I posted an actual problem in advanced physics but no answer so i will try to get an math part answer from it.
Suppose I have to solve this integral:
[itex] I=\int {\vec{dl} × \vec A } [/itex]
Where [itex] \vec A = -\frac {1}{x} \vec a_{z}[/itex]
So it has only a z component and I have to find the vector cross of the field with the contour depicted in the picture
http://pokit.org/get/img/7ea5523fdd63cfc5c9374a07f6ab8bb6.jpg First question:
For the part 3:
If I take that the [itex] \vec dl = - dy \vec {a_y} [/itex] will I integrate from b to c or from c to b?
In my intuition if I took the minus into the account in the differential there is no need for flipping the c and b, so we would integrate from c to b?
When you vector cross this all, there shouldn't be net y component am i right?
Link to thread in physics:
https://www.physicsforums.com/showthread.php?t=630013
Suppose I have to solve this integral:
[itex] I=\int {\vec{dl} × \vec A } [/itex]
Where [itex] \vec A = -\frac {1}{x} \vec a_{z}[/itex]
So it has only a z component and I have to find the vector cross of the field with the contour depicted in the picture
http://pokit.org/get/img/7ea5523fdd63cfc5c9374a07f6ab8bb6.jpg First question:
For the part 3:
If I take that the [itex] \vec dl = - dy \vec {a_y} [/itex] will I integrate from b to c or from c to b?
In my intuition if I took the minus into the account in the differential there is no need for flipping the c and b, so we would integrate from c to b?
When you vector cross this all, there shouldn't be net y component am i right?
Link to thread in physics:
https://www.physicsforums.com/showthread.php?t=630013
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