- #1
Bryson
- 56
- 2
Homework Statement
A stone is dropped of a cliff. A second stone is thrown down the cliff at 10 m/s at 0.5s after the first stone. When do the stones cross paths?
Homework Equations
Yf = vt + at^2/2
The Attempt at a Solution
My logic is the set the final position Yf equal for both stones and solve for time. Keeping in mind for the second stone that t = t + 0.5.
After finding t, simply plug it into the equation to find Yf.
Is this a valid method for solving this problem?
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