Solving Currents & Impedance for 50V, 60 Hz Circuit

In summary, you need to find the current through R, C, and L, and then calculate the total current and total impedance. You can also calculate the angle between R and C. You can then use the |x| and arg(x) functions to find the magnitude and argument of the complex value x.
  • #1
EVriderDK
56
0

Homework Statement



50 volts, 60 Hz
http://peecee.dk/upload/view/363429

I have to find the current through R, C, and L.
Total current.
Totalt impedance.


Homework Equations



I=(U/Z)

The Attempt at a Solution



See picture: http://peecee.dk/upload/view/363430

For I_R it must be (50/150)=0.333. And as it is a resistor, the angle must be 0, so 0.333∠0 ?

On my TI89 i can sum all the currents on complex form, but how to do it in mathcad? On the TI89 it is just (3∠90)+(4∠90) etc.

Thank you in advance.
 
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  • #2
EVriderDK said:

Homework Statement



50 volts, 60 Hz
http://peecee.dk/upload/view/363429

I have to find the current through R, C, and L.
Total current.
Totalt impedance.

Homework Equations



I=(U/Z)

The Attempt at a Solution



See picture: http://peecee.dk/upload/view/363430

For I_R it must be (50/150)=0.333. And as it is a resistor, the angle must be 0, so 0.333∠0 ?

On my TI89 i can sum all the currents on complex form, but how to do it in mathcad? On the TI89 it is just (3∠90)+(4∠90) etc.

Thank you in advance.

In MathCad you can work directly with complex numbers. Just assign R, ZL, ZC variables the appropriate complex values, then write whatever expressions you want with them. Use the |x| operation to find the magnitude of the complex value x. Similarly use the arg(x) function to find the argument, that is angle, of the complex value.

Examples:

attachment.php?attachmentid=46623&stc=1&d=1335295968.gif
 

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  • #4
EVriderDK said:
Thank you!

Well, I'm trying to do this: http://www.ece.uidaho.edu/ee/power/ECE528/Polar PDF.pdf
But what i get is red markings: http://peecee.dk/upload/view/363597

The red highlight that you're seeing on the "j" variable indicates that you're referencing an undefined variable.

When entering i or j to represent ##\sqrt{-1}## then enter them as 1i or 1j, that is, a numeric 1 followed immediately by i or j. The '1' will disappear when the equation is not selected. This serves to distinguish these special variables from mundane variables i and j that you may define and use.
 
  • #5
Thank you! Do you know how only to calculate on polar form?

I want this result as polar, instead of complex: http://peecee.dk/upload/view/363771

And is there away to reset all defined variables? Like r:=r with r and all:=all with all? :)
 
Last edited:
  • #6
EVriderDK said:
Thank you! Do you know how only to calculate on polar form?

I want this result as polar, instead of complex: http://peecee.dk/upload/view/363771

And is there away to reset all defined variables? Like r:=r with r and all:=all with all? :)

I'm not aware of any built-in way to force a result to be displayed in polar form, at least not with the older version of Mathcad that I'm using.

You can "undefine" individual variable numerical values by using them in unfinished assignment statements:

r :=
b :=

etc.

They can be turned into unassigned variables for the symbolic processor by equating them to themselves as you've done. I'm not aware of any way to de-assign all variables in one step.
 
  • #7


THank you for all your help!
 
  • #8


EVriderDK said:
Thank you! Do you know how only to calculate on polar form?

I want this result as polar, instead of complex:

You can define functions to do the conversions. In Mathcad 15, you can define them in such a way as to allow you to put them in the unit placeholder to display results in the way you want.



NR
 

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  • phys - 12 05 28 complex polar notation.jpg
    phys - 12 05 28 complex polar notation.jpg
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  • phys - 12 05 28 complex number polar notation.zip
    10.9 KB · Views: 234
  • #9


Thank you very much again Nemo. That was helpful. Now i can save a couple of steps henceforth ;)
 

Related to Solving Currents & Impedance for 50V, 60 Hz Circuit

FAQs about Solving Currents & Impedance for 50V, 60 Hz Circuit

1. What is the formula for calculating current in a 50V, 60 Hz circuit?

The formula for calculating current in a 50V, 60 Hz circuit is:
Current (I) = Voltage (V) / Impedance (Z).

2. How do I calculate impedance in a 50V, 60 Hz circuit?

To calculate impedance in a 50V, 60 Hz circuit, you will need to know the values for resistance (R) and reactance (X). You can then use the formula:
Impedance (Z) = √(R^2 + X^2).

3. What is the relationship between current and impedance in a 50V, 60 Hz circuit?

In a 50V, 60 Hz circuit, current and impedance have an inverse relationship. This means that as impedance increases, current decreases and vice versa.

4. Can I use the same formula for calculating current and impedance in a 50V, 60 Hz circuit for different frequencies and voltages?

No, the formula for calculating current and impedance in a 50V, 60 Hz circuit is specific to those values. If the frequency or voltage changes, you will need to use different formulas to calculate current and impedance.

5. What are some common sources of impedance in a 50V, 60 Hz circuit?

Some common sources of impedance in a 50V, 60 Hz circuit include resistors, capacitors, and inductors. These components can affect the flow of current in a circuit and contribute to overall impedance.

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