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marinadiamond
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Homework Statement
I am pretty confused with how to go about answering this question:
Calculate the maximum lenth of conveyor which can be used to avoid the belt failing from stress, for an installation carrying 140 t/h up a gradient of 10 degrees, if the belt width is 1.1m, the speed is 1.7 metres per second, the belt uses an 8ply belting and the max working tension is 6 kN/m ply. there's a 2 drum drivehead with an angle of wrap of 400 degrees, the coefficient of grip is 0.2.
Idler coefficients = 0.03 (when belt is empty)
0.04 (for materials)
mass of mivong parts = 65 kg/m
end pulleys etc= 35m of extra empty belt
I have looked into the belt tension equation and put a lot of effort into it, but I'm really confused,
any help in understanding it would be highly appreciated
from a confused beginner!
Homework Equations
Tb = 1.37*f*L*g*[2*mi+ (2*mb + mm)*cos (δ)] + (H*g*mm)
Where,
Tb is in Newton.
f = Coefficient of friction
L = Conveyor length in meters. Conveyor length is approximately half of the total belt length.
g = Acceleration due to gravity = 9.81 m/sec2
mi = Load due to the idlers in Kg/m.
mb = Load due to belt in Kg/m.
mm = Load due to the conveyed materials in Kg/m.
δ = Inclination angle of the conveyor in Degree.
H = vertical height of the conveyor in meters.
The Attempt at a Solution
I genuinely have no idea, i just can't understand what to do, it seems like a completely random task we've been provided
What i do know is
Tb will be somehow derived from the 7.3 kN/m ply
Also, maybe the equation F1/F1= e to the power of mu x alpha
where mu is coefficient of friction alpha is wrap angle
Any input will be highly appreciated!
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