- Thread starter
- #1

#### ATroelstein

##### New member

- Jun 30, 2012

- 15

x

^{3 }<= 7x

^{3}- 24x

^{2}+ 6x - 10

I have worked it out as follows:

0 <= 6x

^{3}- 24x

^{2 }+ 6x - 10

10 <= 6x

^{3}- 24x

^{2 }+ 6x

10 <= 6x(x

^{2}- 4x + 1)

At this point, I'm not sure how to proceed and I'm not sure if the factoring on the last step was helpful. Any advice on how to proceed would be appreciated. Thank you.