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#### alane1994

##### Active member

- Oct 16, 2012

- 126

I have this as part of a calculus problem. I guess I am a little rusty on this. Any help would be appreciated.

[HR][/HR][tex]4\cos^2{x}=\frac{\sec^2{x}}{4}[/tex]

I believe that I need to solve for cosx. And then determine what cosx is in radians. That

[HR][/HR][tex]4\cos^2{x}=\frac{\sec^2{x}}{4}[/tex]

I believe that I need to solve for cosx. And then determine what cosx is in radians. That

*should*be the lower limit of the integration. I know how it should work... it is just the process...
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