Solving a Physics Problem: Net Work Done on a Box

Plugging in the values, we get d = 0 + (1/2)*2*7^2 = 49 meters. Then, using the equation w = f*d*cos(theta), we can find the net work done on the box, which is equal to 490 joules. In summary, to find the net work done on a box of mass 5.0 kg accelerated from rest at a rate of 2.0m/s^2 for 7.0s, we use the kinematic equation d = vi*t + (1/2)*a*t^2
  • #1
APysics
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Homework Statement


a box of mass 5.0 kg is accelerated from rest across a floor at a rate of 2.0m/s^2 for 7.0s. find the net work done on the box.


Homework Equations


f = ma
w= fdcostheta

The Attempt at a Solution


f = ma
f=10

w = fdcostheta
w=10d
w=10*v*t
w=10*v*7
w=10*a*t*7
w = 10*14*7
w=980

the answer is 490...

need help... what am i doing wrong
 
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  • #2
You set the displacement equal to vt. That is incorrect. You will need to use the correct kinematic equation for objects traveling with constant acceleration, to find the displacement.
 
  • #3
thank you!

i got it!
 

Related to Solving a Physics Problem: Net Work Done on a Box

1. What is the definition of net work done on a box in physics?

The net work done on a box is the total amount of energy transferred to or from the box as a result of external forces acting on it. It is a measure of the change in the energy of the box.

2. How is the net work done on a box calculated?

The net work done on a box is calculated by multiplying the force applied to the box by the displacement of the box in the direction of the force. The equation is W = Fd, where W is the net work done, F is the force, and d is the displacement.

3. What factors affect the net work done on a box?

The net work done on a box can be affected by the magnitude and direction of the applied force, as well as the distance over which the force is applied. Other factors such as friction and the weight of the box may also play a role.

4. How does positive and negative net work done affect the motion of a box?

A positive net work done on a box will result in an increase in the box's kinetic energy and cause it to accelerate in the direction of the applied force. On the other hand, a negative net work done will result in a decrease in kinetic energy and cause the box to decelerate or come to a stop.

5. Can the net work done on a box ever be zero?

Yes, the net work done on a box can be zero if the force applied is perpendicular to the displacement of the box. This means that the force is not doing any work on the box, and the net work done is zero. Additionally, if the force and displacement are in opposite directions and have equal magnitudes, the net work done will also be zero.

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